integration
posted by peter .
Find the area of the region under the graph of the function f on the interval [1, 2].
f(x) = 6x + 1
bound by the x axis

Peter, if you are the "anonymous" of
http://www.jiskha.com/display.cgi?id=1291829564
you did not follow my instructions.
the line crosses at x = 1/6, so if the xaxis is the boundary, there are 2 different triangles to consider
left triangle:
base = 5/6
height = 5, Area = (1/2)(5/6)(5) = 25/12
right triangle:
base = 13/6
height = 13 , Area = (1/2)(13/6)(13) = 169/12
total = 25/12 + 169/12 = 97/6
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