posted by Anonymous .
31. (II) a shotputter throws the shot with an initial speed of 15.5m/s at a 34.0* angle to the horizontal. Calculate the horizontal distance traveled by the shots if it leaves the athlete’s hand at a height of 2.20m above the ground.
Break the initial speed into vertical and horizontal components.
Determine the time to hit the ground from the vertical velocity
hf=hi+Viv*t-1/2 g t^2
solve for t.
Then, horizonaldistance= vih*t