A 720ml container holds a mixture of red, yellow, and white paint in a 5:3:12 ratio. How much more red paint than yellow paint is present in the mixture?
Add the ratios together and divide 720 mL in proportion to the ratios.
5+3+12=20
So
red = 720*5/20 = 180 mL
yellow = 720*3/20 = ?
white = 12*3/20 = ?
Add up the three quantities and make sure the sum equals 720 mL.
Thank You!
To find out how much more red paint than yellow paint is present in the mixture, we first need to determine the amount of each type of paint.
Let's assume that the measurements for red, yellow, and white paint in the mixture are 5x, 3x, and 12x, respectively. Here, x represents the scale factor.
Since the total volume of the mixture is 720 ml, we can set up an equation based on the ratio:
5x + 3x + 12x = 720
Combining like terms:
20x = 720
Dividing both sides of the equation by 20:
x = 36
Now that we know the value of x, we can calculate the amounts of red and yellow paint in the mixture.
Red paint = 5x = 5 * 36 = 180 ml
Yellow paint = 3x = 3 * 36 = 108 ml
To find out how much more red paint than yellow paint is present in the mixture, we subtract the amount of yellow paint from the amount of red paint:
180 ml - 108 ml = 72 ml
Therefore, there is 72 ml more red paint than yellow paint in the mixture.