If I have 10mL of 1.0 M Ba(OH)2 solution and add it to 2.5L of water. What is the concentration of hydroxide ions in the diluted Ba(OH)2 solution?
To determine the concentration of hydroxide ions in the diluted Ba(OH)2 solution, we need to first calculate the number of moles of Ba(OH)2 in the original solution, then determine the final volume of the diluted solution, and finally calculate the concentration of hydroxide ions in the diluted solution.
1. Calculate the moles of Ba(OH)2 in the original solution:
Since the concentration of the original solution is given as 1.0 M (moles per liter), we can use the formula: moles = concentration × volume.
moles = 1.0 M × 10 mL = 0.01 moles.
2. Determine the final volume of the diluted solution:
Since we are adding 10 mL of Ba(OH)2 solution to 2.5 L of water, the final volume of the diluted solution will be:
final volume = original volume + added volume = 2.5 L + 10 mL = 2.51 L (converted mL to L).
3. Calculate the concentration of hydroxide ions in the diluted solution:
The hydroxide ions (OH-) in Ba(OH)2 dissociate completely. Since there is one mole of hydroxide ions for one mole of Ba(OH)2, the concentration of hydroxide ions in the diluted solution will be the same as the concentration of Ba(OH)2.
concentration of hydroxide ions = 0.01 moles / 2.51 L = 0.00398 M (rounded to four significant figures).
Therefore, the concentration of hydroxide ions in the diluted Ba(OH)2 solution is approximately 0.00398 M.