How many grams of chloride ions are in 2.5L of a 1.0 M calcium chloride solution?
To find out how many grams of chloride ions are in 2.5L of a 1.0 M calcium chloride solution, we need to use the concept of molarity and the chemical formula of calcium chloride (CaCl2).
The molarity of a solution is defined as the number of moles of solute per liter of solution. In this case, the solute is calcium chloride (CaCl2), and the molarity is given as 1.0 M.
Here's how you can calculate the number of moles of calcium chloride:
Step 1: Calculate the number of moles of calcium chloride using the molarity and volume of the solution:
Number of moles = Molarity x Volume
= 1.0 M x 2.5 L
= 2.5 moles
Step 2: Determine the number of moles of chloride ions. Since there are two chloride ions per calcium chloride molecule, we multiply the number of moles by 2:
Number of moles of chloride ions = 2 x 2.5 moles
= 5 moles
Step 3: Convert the number of moles to grams using the molar mass of chloride ions. The molar mass of chloride ions (Cl-) is approximately 35.45 g/mol:
Mass = Number of moles x Molar mass
= 5 moles x 35.45 g/mol
= 177.25 grams
Therefore, there are approximately 177.25 grams of chloride ions in 2.5L of a 1.0 M calcium chloride solution.