the professinal base ball is 162 games.a player was at bat 3 times in each game, and he played 2/3 of the game.
a.how many times was the player at bat during the season?
b.the player hit o.250., which means he got a hit 25%of the time , or once in every four bats . how many hits did he get during the year?
(2/3) * 162 = 324/3 = 108
3 * 108 = 324 times at bat
0.25 * 324 = ? hits
.81
Thx
To answer these questions, let's break them down step by step:
a. How many times was the player at bat during the season?
To find the number of times the player was at bat during the season, we need to multiply the number of games by the number of times the player was at bat per game.
Given:
Number of games in a season = 162
Number of times player was at bat per game = 3
Formula:
Number of times player was at bat during the season = Number of games * Number of times player was at bat per game
Applying the values from above:
Number of times player was at bat during the season = 162 * 3
Number of times player was at bat during the season = 486
Therefore, the player was at bat 486 times during the season.
b. How many hits did the player get during the year?
To find the number of hits the player got during the year, we need to calculate the percentage of hits he made during each at-bat and then multiply it by the total number of times he was at bat.
Given:
Percentage of hits per at-bat = 25% (or 0.25)
Number of times player was at bat during the season = 486
Formula:
Number of hits = Percentage of hits per at-bat * Number of times player was at bat during the season
Applying the values from above:
Number of hits = 0.25 * 486
Number of hits = 121.5
As the number of hits should be a whole number because it represents the total number of successful hits, we round the result down to the nearest whole number.
Therefore, the player had 121 hits during the year.