Calculus

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Find the point on the graph of y=2x-4 that is closest to the point (1,3). (Optimization equation)

  • Calculus -

    D^2=f(x)= (x-1)^2+((2x-4)-3)^2
    f'(x)= 2(x-1)(1)+2(2x-7)(2)
    0= 2x-2+(4x-14)2
    0= 2x-2+8x-28
    0= 10x-30
    30=10x
    x=3
    y=2(3)-4
    y=2
    (3,2)

    the square over D doesn't matter.

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