The sum of two numbers is 44. The second number is 5 more than twice the first. Find the numbers.
x+y=44
2x+5y
Is this correct? So the answer would be 3x + 6y=44?
a=first number
b=second number
a+b=44
b=5+2a
a+b=a+5+2a =3a+5= 44
3a+5=44
3a=44-5
3a=39 Divided with 3
3a/3=39/3
a=13
b=5+2a
b=5+2*13
b=5+26
b=31
a+b=13+31=44
Gr8 you made that look SO freakin easy! :D Thank you very much
No, the equation you wrote, 3x + 6y = 44, is not correct. Let's go through the problem step-by-step to find the correct equations.
Let's represent the first number as x and the second number as y.
1. The sum of two numbers is 44: x + y = 44.
2. The second number is 5 more than twice the first: y = 2x + 5.
So the correct equations are x + y = 44 and y = 2x + 5.
No, your equations are not correct. Let's go through the problem step by step to find the correct equations.
Let's assume the first number is represented by x and the second number is represented by y.
From the problem statement, we know two things:
1. The sum of the two numbers is 44, so the equation would be: x + y = 44.
2. The second number is 5 more than twice the first, so the equation would be: y = 2x + 5.
Now, let's solve these equations simultaneously to find the values of x and y.
We can start by substituting the value of y from the second equation into the first equation:
x + (2x + 5) = 44.
Simplifying this equation, we get:
3x + 5 = 44.
Now, subtract 5 from both sides of the equation:
3x = 39.
Divide both sides by 3 to isolate x:
x = 13.
Now that we have the value of x, we can substitute it back into either of the original equations to find the value of y. Let's substitute it into the second equation:
y = 2(13) + 5 = 26 + 5 = 31.
So, the two numbers are x = 13 and y = 31.