if you combust 30kg of octane (about the amount in one tank for a small car), how many kilograms of CO2 will you emit?

Octane has a chemical formula of C8H18.

For complete combustion, the reaction is:

2C8H18 + 25O2 -> 16CO2 + 18H2O + heat

RMM(C8H18)=114
RMM(CO2) = 44

So 2*114 grams of Octane will produce 16*44 grams of CO2.

Can you take it from here?

Check my calculations.

To determine the amount of CO2 emitted from combusting 30kg of octane, we need to consider the molecular composition of octane and its combustion reaction.

Octane (C8H18) is an organic compound commonly found in gasoline. When octane reacts with oxygen (O2) during combustion, it produces carbon dioxide (CO2) and water (H2O) as byproducts. The balanced equation for the combustion reaction of octane is as follows:

2 C8H18 + 25 O2 -> 16 CO2 + 18 H2O

From the equation, we can see that for every 2 moles of octane, 16 moles of CO2 are produced. The molar mass of octane (C8H18) is approximately 114 grams/mol, while the molar mass of carbon dioxide (CO2) is about 44 grams/mol.

Now, let's calculate the amount of CO2 produced:

1. Convert the mass of octane from kilograms to grams:
30 kg * 1000 = 30000 grams

2. Convert the mass of octane to moles:
Moles of octane = Mass / Molar mass
Moles of octane = 30000 g / 114 g/mol ≈ 263.2 mol (rounded to 3 decimal places)

3. Calculate the moles of CO2 produced:
Moles of CO2 = Moles of octane × (16 mol CO2 / 2 mol octane)
Moles of CO2 = 263.2 mol × (16 / 2) ≈ 2105.6 mol (rounded to 3 decimal places)

4. Convert the moles of CO2 to mass in kilograms:
Mass of CO2 = Moles of CO2 × Molar mass
Mass of CO2 = 2105.6 mol × 44 g/mol ≈ 92,508.4 g (rounded to 1 decimal place)

Finally, the amount of CO2 emitted from combusting 30kg of octane is approximately 92,508.4 grams or 92.5 kilograms.