what is the condensed structure for the reactants and products of the following: cis-2-chloro-2-butene + HI-----> ??

To determine the condensed structure for the reactants and products of the given reaction, cis-2-chloro-2-butene + HI, we need to first understand the reactants and products individually.

Cis-2-chloro-2-butene: This is a compound with a double bond and a chlorine atom attached to one of the carbon atoms adjacent to the double bond. The "cis" prefix indicates that the substituents (chlorine atom and hydrogen atoms) are on the same side of the double bond.

HI: HI stands for hydroiodic acid, which is composed of hydrogen (H) and iodine (I). It is an acid commonly used in organic chemistry reactions as a source of iodine.

Now, let's determine the condensed structure for the reactants and products:

Reactants:
cis-2-chloro-2-butene + HI

The condensed structure for cis-2-chloro-2-butene can be represented as follows:
CH3CH(Cl)CH=CH2

The condensed structure for hydroiodic acid (HI) is written as:
HI

Products:
To determine the products, we need to consider the reaction between cis-2-chloro-2-butene and hydroiodic acid (HI). In this case, the double bond in cis-2-chloro-2-butene reacts with the hydrogen (H) from HI, resulting in the addition of an H and an I atom to the compound.

The product will be 2-iodo-2-chlorobutane, and the condensed structure is represented as:
CH3CH(I)CH(Cl)CH3

Therefore, the condensed structure for the reactants and products of the given reaction cis-2-chloro-2-butene + HI is:

Reactants:
cis-2-chloro-2-butene: CH3CH(Cl)CH=CH2
HI

Products:
2-iodo-2-chlorobutane: CH3CH(I)CH(Cl)CH3