Calculate the freezing point of each of the solution 75.0 of glucose,C6H12O6 , added to 9.30×10−2 of water.... Please help
75.0G *
To calculate the freezing point of a solution, we need to use the equation for freezing point depression:
ΔTf = Kf * i * m
where:
- ΔTf is the change in freezing point
- Kf is the cryoscopic constant (which depends on the solvent)
- i is the van't Hoff factor (the number of particles the solute dissociates into)
- m is the molality of the solution (moles of solute per kilogram of solvent)
In this case, the solute is glucose (C6H12O6) and the solvent is water. We need to find the molality of the solution and the van't Hoff factor.
1. Calculate the molality:
Molality (m) is the moles of solute divided by the mass of solvent (in kg).
Given that 75.0 g of glucose is added to 9.30×10^−2 kg of water, we can convert the mass of glucose to moles using its molar mass (180.16 g/mol):
moles of glucose = 75.0 g / 180.16 g/mol
Next, we divide the moles of glucose by the mass of water in kg:
m = moles of glucose / mass of water in kg
2. Determine the van't Hoff factor (i):
The van't Hoff factor depends on the extent to which the solute dissociates in the solvent. In the case of glucose in water, it does not dissociate, so i = 1.
3. Find the cryoscopic constant (Kf) for water:
For water, the cryoscopic constant is approximately 1.86°C/m.
4. Calculate the change in freezing point (ΔTf):
ΔTf = Kf * i * m
Finally, subtract the change in freezing point from the normal freezing point of pure water (0°C) to obtain the freezing point of the solution.
Please provide the values for the mass of glucose and water to proceed with the calculation.