Someone please help me not sure if I even know what I am doing with any of this.
write the following ratios in simplest form 5 3/5 to 2 1/10 5 3/5 2 1/10 x 100/100 = 8/20 = 2/5
the ratio of 7 dimes to 3 quarters
7/3 x 100/100 = 700/300 = 175/75
solve the following applications
an algebra class has 7 men and 13 women. write the ratio of women to men. 7 men 13 women x 100/100 = 700/1300= 175/325
Marc took 3 hours to mow a lawn while Angelina took 150 minutes to mow the same lawn a week earlier. Write the ratio of Marc time to Angelina time as a ratio whole numbers. 3h/150 min. x 100/100 = 300/15,000 = 75/ 1875
find the rate 240 pounds of fertilizer/ 6 lawns.
240/6 x 100/1= 24000/6= 4000
which is the better buy 5lb of sugar $4.75 or 20lb for $19.92?
4.75/5x100/1=475/5=95 19.92/20x100/1= 19.922/20=0.996
write the proportion that is equivalent to given statement
If Maria hit 8 home runs in 15 softball games, then she should hit 24 home runs in 45 games.
8/15 x 24/45 = 360
determine whether each pair of fraction is proportional.
5/8 x 75/120 = 600/600
determine if the given rates are equivalent.
12 gallons of paint/8,329 ft2 ? 9 gallons of paint/ 1,240 ft2 = not equivalent.
A store has t-shirts on sale 2 for $5.50. at this rate how much does 5 t-shirts cost?
$5.50/5 = $1.10
assume a 150lb person.
if a person jogs at a rate of 5 1/2mi/h
for 3 1/2h in a week, how many calories do they burn? 60
if a person runs in place for 15 minutes, how many calories will be burned? 9,750
if a person cross country skis for 35 minutes, how many calories will be burned? 24,500
how many hours would a person have to jump rope in order to lose 1 pound? (assume calorie consumption is just enough to maintain weight, with no activity.) 750
heavier people burn more calories (for the same activity), and lighter people burn fewer. In fact, you can calculate similar figures for burning calories by setting up the appropriate proportions.
at what rate would a 120lb person burn calories while bicycling at 12mi/h? 1,440
at what rate would a 180lb person burn calories while bicycling at 12 mi/h? 2,160
how many hours of jogging at 5 1/2 mi/h would be needed for a 200lb person to lose 5lb? (again assume calorie consumption is just enough to maintain weight with no activity.) 500
Don't understand your first problem. I won't do all of your problems for you.
7 dimes = $.70, 3 quarters = $.75, therefore 70/75 (Reduce.)
Why do you multiply by 100/100? 7/13
Lawn = 3/2.5
Why do you multiply by 100? 240/6 = 40 lbs./lawn
Sugar $4.75/5 = $.95/lb., $19.92/20 = $.97/lb. Decimal place for first answer is off.
8/15 = 24/45 home runs per game.
Fractions: 5/8, 75/120 reduces to 5/8, divide numerator and denominator by 5 = 15/24, divide by 3 = 5/8
Shirts 5.5/2 = x/5, solve for x.
Inadequate data for calorie problems. Do you have a chart with rate of burning calories/body weight for each activity? Different activities burn calories at different rates. Typically, you would need to change caloric intake by 3500 calories to lose one pound.
1. 5 3/5 / 2 1/10.
(28/5) / (21/10) =
28/5 * 10/21 = 280/105 = 8/3.
2. 7 Dimes / 3 qtrs =
(7 * 10) / 3 * 25) = 70 / 75 = 14/15.
3. 13 / 7.
4. 3 / 2 1/2 = 3 / (5/2) 3 * 2 / 5 = 6/5.
5. 240 / 6 = 40 / 1.
6. 4.75 / 5 = $0.95 / lb.
19.92 / 20 = $0.996 / lb
7. 8/15 = 24/45.
8. 5/8 = 75/120. yes.
To write ratios in simplest form, you need to simplify the fractions and reduce them to the lowest terms. Here's how you can do it:
1. For the ratio 5 3/5 to 2 1/10:
- Convert mixed numbers to improper fractions:
5 3/5 = (5 * 5 + 3) / 5 = 28/5
2 1/10 = (2 * 10 + 1) / 10 = 21/10
- Multiply both fractions by 100/100 to eliminate the decimals:
(28/5) * (100/100) = 2800/500
(21/10) * (100/100) = 2100/1000
- Simplify the fractions by canceling out common factors:
2800/500 = 28/5 = 5 3/5
2100/1000 = 21/10 = 2 1/10
- The simplified ratio is 5 3/5 to 2 1/10 = 28/5 to 21/10 = 2/5.
2. For the ratio of 7 dimes to 3 quarters:
- Simply write the ratio as 7/3.
- Since the question asks for the simplest form, no further simplification is required.
3. For the ratio of women to men in an algebra class with 7 men and 13 women:
- Write the ratio as 13/7.
- Multiply both fractions by 100/100 to get rid of the decimal points.
- Simplify the fractions as much as possible.
4. For the ratio of Marc's time to Angelina's time in mowing the lawn (3 hours vs. 150 minutes):
- Convert Marc's time to minutes: 3 hours * 60 minutes/hour = 180 minutes.
- Write the ratio as 180/150.
- Multiply both fractions by 100/100.
- Simplify the fractions as much as possible.
5. For the rate of 240 pounds of fertilizer in 6 lawns:
- Write the rate as 240/6.
- Multiply the fraction by 100/1 to eliminate decimals.
- Simplify the fraction as much as possible.
For the rest of the questions, follow the same steps of writing the fractions or ratios and simplifying them to their simplest form if necessary. Remember to convert units if needed and apply appropriate calculations.