Suppose two dice (one red, one green) are rolled. Consider the following events.

A: the red die shows 5.
B: the numbers add to 4.
C: at least one of the numbers is 3.
D: the numbers do not add to 10.
Express the event "The numbers do not add to 4." in symbols.
1
B D D' B' B' ∪ D

How many elements does it contain?
2

B : the numbers add to 4.

D : the numbers do not add to 10
D' : is the complement of D, i.e.
the numbers add to 10
B' : is the complement of B
______________________

B' ∪ D : is the complement of B or D
= the numbers do not add up to four or the numbers do not add to 10

The event "The numbers do not add to 4" can be expressed in symbols as B'.

This event contains 1 element.

The event "The numbers do not add to 4" can be expressed symbolically as B', which means the complement of event B (the numbers add to 4). To calculate how many elements it contains, we need to determine the number of outcomes that satisfy event B and subtract it from the total number of possible outcomes.

To find the number of outcomes that satisfy event B, we need to determine all the possible pairs of numbers from the two dice that add up to 4. The possible pairs that satisfy this condition are (1, 3), (2, 2), and (3, 1). So there are 3 outcomes that satisfy event B.

Now, let's determine the total number of possible outcomes when rolling two dice. Each die has 6 sides, so the total number of outcomes is 6 * 6 = 36.

Therefore, the event B' (the numbers do not add to 4) contains 36 - 3 = 33 elements.