How many mL of a 0.90% (m/v) NaCl stock solution will you need to to prepare 250 mL of a 0.225% m/v NaCl solution?
The dilution formula, which works for M, m, and N (perhaps others) is
mL x % = mL x %.
Substitute and solve for mL.
225
To find out how many mL of a 0.90% (m/v) NaCl stock solution you will need to prepare 250 mL of a 0.225% (m/v) NaCl solution, we can use the concept of dilution.
The formula for dilution is:
C1V1 = C2V2
Where:
C1 = concentration of the stock solution
V1 = volume of the stock solution
C2 = concentration of the desired solution
V2 = volume of the desired solution
Let's plug in the values we have:
C1 = 0.90% (m/v)
V1 = ?
C2 = 0.225% (m/v)
V2 = 250 mL
First, let's convert the percentages to decimal form by dividing by 100:
C1 = 0.009 (m/v)
C2 = 0.00225 (m/v)
Now we can rearrange the equation to solve for V1:
V1 = (C2V2) / C1
V1 = (0.00225 * 250) / 0.009
V1 ≈ 62.5 mL
Therefore, you will need approximately 62.5 mL of the 0.90% (m/v) NaCl stock solution to prepare 250 mL of a 0.225% (m/v) NaCl solution.