physics
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Figure 643 shows a "conical pendulum", in which the bob (the small object at the lower end of the cord) moves in a horizontal circle at constant speed. (The cord sweeps out a cone as the bob rotates.) The bob has a mass of 0.060 kg, the string has length L = 0.90 m and negligible mass, and the bob follows a circular path of circumference 0.90 m.
What is the period of the motion? The tension in the string is 0.596N.

physics 
drwls
The halfangle at the apex of the cone is theta = sin^1[0.9/2 pi)/0.9]
= sin^1(1/2 pi)
= 9.1 degrees
See http://en.wikipedia.org/wiki/Conical_pendulum
for the period of a conical pendulum. At this rather small cone angle, the period will be nearly the same as that of a normal pendualum of the same length. 
physics 
Anonymous
4sin^2(theta)  2sin(theta)  2 = 0 on the interval 0 (less than or equal to ) theta < 2(pi)?
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