posted by .

If f(x)=8x +2 find the exact area under the curve from x=0 to x=2.

  • calculus -

    You do not need Calculus for this question, since this results in a trapezoid.
    The two parallel sides have lengths of 2 and 18 and the distance between them is 2

    Area = 2(2+18)/2 = 20

    if you insist on Calculus

    Area = [integral](8x+2)dx from 0 to 2
    = |4x^2 + 2x| from 0 to 2
    = 16 + 4 - 0 = 20

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. CALC - area under a curve

    You have an unknown function that is monotone increasing for 1<x<5 and have the following information about the function values. With the clear understanding that there is no way to get an exact integral, how would you try and …
  2. Calculus

    Integrals: When we solve for area under a curve, we must consider when the curve is under the axis. We would have to split the integral using the zeros that intersect with the axis. Would this be for all integrals?
  3. calculus

    suppose that the area under the curve y=1/x from x=a to x=b is k. the area in terms of k, under the curve y=1/x from x=2a to x=2b?
  4. Calculus ll - Improper Integrals

    Find the area of the curve y = 1/(x^3) from x = 1 to x = t and evaluate it for t = 10, 100, and 1000. Then find the the total area under this curve for x ≥ 1. I'm not sure how to do the last part of question ("find the the total …
  5. Calculus

    Find the exact area below the curve (1-x)*x^9 and above the x axis
  6. calculus

    Find area of the region under the curve y = 5 x^3 - 9 and above the x-axis, for 3¡Ü x ¡Ü 6. area = ?
  7. Calculus I

    Section Area: Use Riemann sums and a limit to compute the exact area under the curve. y = 4x^2 - x on (a) [-0,1]; (b) [-1, 1]; (c) [1, 3]
  8. Calculus

    Find the exact area below the curve y=x^3(4-x)and above the x-axis
  9. Calculus

    Find the area cut off by x+y=3 from xy=2. I have proceeded as under: y=x/2. Substituting this value we get x+x/2=3 Or x+x/2-3=0 Or x^2-3x+2=0 Or (x-1)(x-2)=0, hence x=1 and x=2 are the points of intersection of the curve xy=2 and the …
  10. calculus

    Find the exact area of the surface obtained by rotating the curve about the x-axis. y=((x^3)/4)+(1/3X), 1/2≤X≤1

More Similar Questions