An arrow is shot from a bow at 42 m/s at 70 degrees what is the horizontal and vertical components
how is the 70 degrees measured? from the horizontal?
horizontal=42*cos70
vertical=42*sin70
An arrow is fired from a bow with a velocity of 48 m/s at at an angle of 70 degreesto the hoizontal. What are the verical and hoizontal components of the arrows velocity?
To find the horizontal and vertical components of the arrow's velocity, we can use trigonometry. The initial velocity of the arrow can be represented as V = 42 m/s and the angle it makes with the horizontal can be represented as theta = 70 degrees.
The horizontal component (Vx) represents the velocity of the arrow in the x-direction (parallel to the ground), while the vertical component (Vy) represents the velocity in the y-direction (perpendicular to the ground).
To find Vx, we can use the formula Vx = V * cos(theta), where cos(theta) represents the cosine of the angle theta.
To find Vy, we can use the formula Vy = V * sin(theta), where sin(theta) represents the sine of the angle theta.
Now, let's calculate the values:
Vx = 42 m/s * cos(70 degrees)
Vy = 42 m/s * sin(70 degrees)
Using a scientific calculator, we can find:
Vx ≈ 42 m/s * 0.34202 ≈ 14.36484 m/s
Vy ≈ 42 m/s * 0.93969 ≈ 39.59098 m/s
Therefore, the horizontal component is approximately 14.36 m/s, and the vertical component is approximately 39.59 m/s.