Math
posted by Ana .
<D is complentary to <E and <D is supplementary to <G
If the measure of <E is 78
find the measure of <D and <G

D+E=90 ... (1)
D+G=180 ... (2)
Given E=78,
Solve for D from (1), and hence G from (2). 
<D=12
<G=118
??? 
Let's do a check:
From (1)
D+E=90 => 12+78=90 OK
From (2)
D+G=180 => 12+118=130 ≠ 180 ??
Let's solve for G from (2):
D+G=180
12+G=180
1212+G = 18012
G=168
Post if it's still not clear.
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