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posted by csb Sunday, December 5, 2010 at 1:07pm.

What volume of 0.115M NaOH is required to reach the equivalence point in the titration of 25.00 mL of 0.200M of HF? Ka(HF)=7.4 x 10^-4

Ka is not needed. mL x M = mL x M.

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