how many moles of oxygen are needed to react with 1.6 moles of isopropyl alcohol, CcH7OH Equation is 2 C3H7OH + 9 02 ->6 CO2 + * H2O
7.2
see above.
To determine the number of moles of oxygen needed to react with 1.6 moles of isopropyl alcohol (C3H7OH), we need to look at the balanced chemical equation:
2 C3H7OH + 9 O2 → 6 CO2 + * H2O
From the equation, we can see that 2 moles of isopropyl alcohol react with 9 moles of oxygen.
Therefore, we can set up a ratio:
9 moles of oxygen / 2 moles of isopropyl alcohol = x moles of oxygen / 1.6 moles of isopropyl alcohol
Cross-multiplying and solving for x:
9 moles of oxygen = (2 moles of isopropyl alcohol * x moles of oxygen) / 1.6 moles of isopropyl alcohol
Simplifying:
9 moles of oxygen = (2/1.6) * x moles of oxygen
9 moles of oxygen = 1.25x moles of oxygen
Dividing both sides by 1.25:
x = (9 moles of oxygen) / 1.25
x ≈ 7.2 moles of oxygen
Therefore, approximately 7.2 moles of oxygen are needed to react with 1.6 moles of isopropyl alcohol.
To determine the number of moles of oxygen needed to react with 1.6 moles of isopropyl alcohol (C3H7OH), we can use the balanced equation provided:
2 C3H7OH + 9 O2 -> 6 CO2 + * H2O
The coefficient in front of O2 in the balanced equation is 9, which indicates that for every 9 moles of O2, 2 moles of isopropyl alcohol react.
To find the number of moles of O2 needed to react with 1.6 moles of isopropyl alcohol, we can set up a ratio:
9 moles O2 / 2 moles C3H7OH = x moles O2 / 1.6 moles C3H7OH
Cross-multiplying and solving for x, we have:
9 moles O2 * 1.6 moles C3H7OH = 2 moles C3H7OH * x moles O2
14.4 moles O2 = 2x moles O2
Dividing both sides by 2, we get:
x moles O2 = 14.4 moles O2 / 2
x moles O2 = 7.2 moles O2
Therefore, 7.2 moles of oxygen are needed to react with 1.6 moles of isopropyl alcohol.