posted by Ivy .
A 19.18 mL of 0.125 M Oxalic Acid (H2C2O42H2O) is titrated with a Ca (OH)2
solution. The initial volume of Ca(OH)2 was 14.38 and the final volume of
Ca(OH)2 was 28.29 mL when the solution turned very slightly pink. What is the
concentration of Ca (OH)2?
H2Ox + Ca(OH)2 ==> CaOx + 2H2O
moles H2Ox = M x L = ??
moles Ca(OH)2 = same as H2Ox because the equation shows the reaction is 1:1.
Then M Ca(OH)2 = mols/L
You know, of course, to find the volume of Ca(OH)2 that you subtract the final volume from the initial volume.
Why is it H2Ox instead of H2C2O4?