Physics
posted by Jesse .
A baseball is released at rest from the top of the washington Monument. It hits the ground after falling for 6.0 s. What was the height from which the ball was dropped? (g=9.8 m/s2 and assume air resistance is negligible)

h=1/2 g t^2

The distance it falls in time t is
Y = (1/2) g t^2.
That is a formula you need to learn.
Apply it. 
y = (1/2)(9.80 m/s2)(6.0s)^2
y = (4.9 m/s2)(36.0s2)
y = 176.4 m
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