Henry drives off a 200m high cliff at 132m/s.How far out,how far down,and how far all together did he travel in 2.6seconds
To find how far out, down, and all together Henry traveled, we can use a kinematics equation:
1. First, let's find how far down Henry traveled using the equation:
h = ut + (1/2)gt^2
where h is the height, u is the initial velocity, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time.
Substituting the given values:
h = (132 m/s)(2.6 s) + (1/2)(9.8 m/s^2)(2.6 s)^2
h = 343.2 m
Therefore, Henry traveled 343.2 meters down.
2. Next, let's find how far out Henry traveled horizontally. Since there is no acceleration horizontally, the distance will be given by:
d = v * t
where d is the distance, v is the horizontal velocity, and t is the time.
Substituting the given values:
d = (132 m/s)(2.6 s)
d = 343.2 m
Therefore, Henry traveled 343.2 meters out.
3. Lastly, let's find the total distance traveled by finding the hypotenuse of a right triangle formed by the horizontal and vertical distances:
Total distance = √[(h^2) + (d^2)]
Substituting the calculated values:
Total distance = √[(343.2 m)^2 + (343.2 m)^2]
Total distance ≈ 485.24 m
Therefore, Henry traveled approximately 485.24 meters all together.