Post a New Question


posted by .

A 0.70 kg ball is moving horizontally with a speed of 8.8 m/s when it strikes a vertical wall. The ball rebounds with a speed of 3.7 m/s. What is the magnitude of the change in linear momentum of the ball?
-I am not sure how to honestly to figure this one out.

  • physics -

    Mass times velcity change.

    0.70 kg*[8.8 -(-3.7] m/s
    = 0.70 kg*12.4 m/s
    = ____ kg*m/s

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question