There are 2 opaque bags, each containing red and yellow blocks. Bag 1 contains 3 red blocks and 5 yellow. Bag 2 contains 5 red and 15 yellow. To play the game, you pick a bag and then you pick a block out of the bag without looking. Would a person be more likely to pick a red block if she picks from bag 2 rather than bag 1? Explain
Pr(red|bag1)=3/8
pr(red|bag2)=5/20
which is the higher probability?
you have bag candy a total of 125, 20 red 27 green 15 yield 35 brown 15 blue what the faction.
To determine if a person would be more likely to pick a red block from Bag 2 rather than Bag 1, we need to compare the probabilities of selecting a red block from each bag.
Let's start with Bag 1. We know that Bag 1 contains a total of 3 red blocks and 5 yellow blocks. To find the probability of selecting a red block from Bag 1, we divide the number of red blocks by the total number of blocks in the bag:
Probability of selecting a red block from Bag 1 = Number of red blocks in Bag 1 / Total number of blocks in Bag 1
= 3 / (3 + 5)
= 3 / 8
So the probability of picking a red block from Bag 1 is 3/8.
Now let's move on to Bag 2. Bag 2 contains 5 red blocks and 15 yellow blocks. Using the same formula as before, we can calculate the probability of selecting a red block from Bag 2:
Probability of selecting a red block from Bag 2 = Number of red blocks in Bag 2 / Total number of blocks in Bag 2
= 5 / (5 + 15)
= 5 / 20
= 1 / 4
Therefore, the probability of picking a red block from Bag 2 is 1/4.
Comparing the probabilities, we can see that the probability of picking a red block from Bag 2 (1/4) is higher than the probability of picking a red block from Bag 1 (3/8). Therefore, a person would be more likely to pick a red block if they choose from Bag 2 rather than Bag 1.