{Hello everyone i'm back}:)
I have a problem..: Kevin has 5 containers of chocolate. The first container has 110 peices of chocolate, the third container has twice as many peices of chocolate as the second container and the fourth container has half as many peices as the first container. How many peices of chocolate does Kevin have if the fifth container has 60 peices of chocolate and the second has five less than the fifth?[I'm so confused, i need help immediately],Thank you!
1st- 110
2nd- 55
3rd- 110
4th- 55
5th- 60
Pretty sure that's correct
That'll be all. That's how i would need to set it up just like that?
Hello! I'm here to help you solve the problem.
To find the total number of pieces of chocolate Kevin has, we need to find the number of pieces in each container and then sum them up. Let's break down the information given step by step:
1) The first container has 110 pieces of chocolate.
2) The third container has twice as many pieces as the second container.
3) The fourth container has half as many pieces as the first container.
4) The fifth container has 60 pieces of chocolate.
5) The second container has five less than the fifth container.
Now, let's calculate the number of chocolate pieces in each container:
1) The first container: 110 pieces.
2) The fifth container has 60 pieces and the second container has five less than the fifth container, so the second container has 60 - 5 = 55 pieces.
3) The third container has twice as many pieces as the second container, so it has 2 * 55 = 110 pieces.
4) The fourth container has half as many pieces as the first container, so it has 110 / 2 = 55 pieces.
Finally, let's sum up the number of pieces in all the containers:
110 (first container) + 55 (second container) + 110 (third container) + 55 (fourth container) + 60 (fifth container) = 390 pieces of chocolate.
Therefore, Kevin has a total of 390 pieces of chocolate.