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From the following information, determine ΔH°f of malonic acid, CH2(COOH)2(s).
CH2(COOH)2(s) + 2O2(g) → 3CO2(g) + 2H2O(l); ΔH° = –861.0 kJ
ΔH°f (kJ/mol)

A. 2613.1 kJ
B. –1540.3 kJ
C. –2613.1 kJ
D. 891.1 kJ
E. –891.1 kJ

  • chemistry -

    delta Hrxn = (delta H products)-(delta H reactants)
    delta H products = 3*CO2 + 2*H2O
    delta H reactants = X
    delta H rxn given.

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