If a shopkeeper sold 15 boxes of pencils on Mon and Tues. He sold 3 more boxes on Mon then on Tues. There were 12 pencils in each box. How many pencils did he sell on Monday.
M + T = 15
M = T + 3
--------------
2 T + 3 = 15
T = 6 boxes on Tues
so
9 boxes on Monday
9*12 = 108
thank you very much damon!
You are welcome :)
How did you get the answer 9 on Monday and 6 on Tuesday? Why Monday couldn’t be 10 and Tuesday couldn’t be 5?
To find the number of pencils sold on Monday, we need to determine the number of boxes sold on Monday. Let's break down the information provided step by step:
1. The shopkeeper sold a total of 15 boxes of pencils on Monday and Tuesday.
2. The shopkeeper sold 3 more boxes on Monday than on Tuesday.
Let's use some variables to help us solve the problem:
Let "x" represent the number of boxes sold on Tuesday.
Then, "x + 3" would represent the number of boxes sold on Monday.
Since there are 12 pencils in each box, we can calculate the total number of pencils sold on each day by multiplying the number of boxes by 12.
So, on Tuesday, the shopkeeper sold a total of "x * 12" pencils.
And on Monday, the shopkeeper sold a total of "(x + 3) * 12" pencils.
However, we know that the total number of boxes sold on Monday and Tuesday combined is 15. Therefore, we can set up an equation to solve for "x":
x + (x + 3) = 15.
Simplifying the equation, we get:
2x + 3 = 15.
2x = 15 - 3.
2x = 12.
x = 6.
So, the shopkeeper sold 6 boxes of pencils on Tuesday.
To find out how many pencils were sold on Monday, we substitute the value of "x" into the equation:
(x + 3) * 12 = (6 + 3) * 12 = 9 * 12 = 108.
Therefore, the shopkeeper sold 108 pencils on Monday.