College Algebra
posted by Laura Hieb .
Only 27% of the carbon14 in a wooden bowl remains. How old is the bowl? (Carbon14 has a halflife of 5,700 years.)

Let T be the age in years.
0.27 = (0.5)^(T/5700)
Take logs of both sides to solve.
T/5700 = log(0.27)/log(0.5) = 1.889
T = ___ years 
65437990

well the bowel has 27% carbon14 remaining which means that 73% of the carbon14 has already been depleted. 5700 years is the half life of carbon14 so to get the full life we multiply 5700(2)=11400 years. then we can do an easy cross multiplication problem to figure it out, x/11400=73/100 and then we solve for x which is x=11400(73)/100 and the final answer and age of the bowel is 8322 years. a very algebraic way of solving it lol
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