if 500 ml of HCl solution is needed to react with 2.43 g of Mg, what is the molarity of the HCl solution?
Mg + 2HCl ==> NgCl2 + H2
mols Mg = grams/molar mass
Convert moles Mg to moles HCl using the coefficients in the balanced equation.
Convert moles HCl to volume using M = moles/L.
The hydrogen generated in lab is a product of reaction between magnesium and hydrochloric acid. Which of these reacts was the limiting reactant?
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To find the molarity of the HCl solution, we need to first determine the number of moles of HCl and then divide it by the volume of the solution.
1. Start by calculating the number of moles of Mg:
- The molar mass of Mg is 24.31 g/mol.
- Divide the given mass of Mg by its molar mass:
moles of Mg = 2.43 g / 24.31 g/mol
2. The balanced chemical equation for the reaction between HCl and Mg is:
Mg + 2HCl -> MgCl2 + H2
3. From the balanced equation, we can deduce that one mole of Mg reacts with two moles of HCl.
4. Since the stoichiometry is 1:2 (Mg:HCl), the number of moles of HCl needed will be twice the number of moles of Mg calculated in step 1:
moles of HCl = 2 * moles of Mg
5. Now, we can find the molarity of the HCl solution by dividing the moles of HCl by the volume in liters:
Molarity (M) = moles of HCl / volume of solution (L)
However, we are given the volume in milliliters (ml), so we need to convert it to liters:
volume of solution (L) = 500 ml / 1000 = 0.5 L
6. Finally, substitute the values into the equation from step 5 to find the molarity:
Molarity (M) = moles of HCl / volume of solution (L)