A 500 kg car moves along a horizontal road. The car moves with an acceleration 2.5 m/s2 by a driving force of 2500 N when the air resistance is 400 N. Find the friction of the tyre of the car.
Net force= m*acceleration
2500N-400-roadfriction= m*a
solve for road friction.
You are driving a 2520.0-kg car at a constant speed of 14.0 m/s along a wet, but straight, level road. As you approach an intersection, the traffic light turns red. You slam on the brakes. The car's wheels lock, the tires begin skidding, and the car slides to a halt in a distance of 25.8 m. What is the coefficient of kinetic friction between your tires and the wet road?
Joe wishes to hang a sign weighing 705 N so that cable A, attached to the store, makes a 30.0° angle, as shown below. Cable B is horizontal and attached to an adjoining building. What is the tension in cable B?
To find the friction force, we need to consider the forces acting on the car. The driving force, air resistance, and friction force all contribute to the car's motion.
The driving force is given as 2500 N. This force accelerates the car with an acceleration of 2.5 m/s^2. We know that force is equal to mass multiplied by acceleration (F = m * a), so we can rearrange the formula to find the mass of the car.
F = m * a
2500 N = m * 2.5 m/s^2
Dividing both sides by 2.5, we get:
m = 2500 N / 2.5 m/s^2 = 1000 kg
Now that we know the mass of the car is 1000 kg, we can find the total force acting on the car, which is the sum of the driving force and the air resistance.
Total force = driving force - air resistance
Total force = 2500 N - 400 N = 2100 N
Finally, the friction force can be calculated as the difference between the total force and the driving force.
Friction force = Total force - Driving force
Friction force = 2100 N - 2500 N = -400 N
The negative sign indicates that the friction force is in the opposite direction of the driving force. Therefore, the friction force of the tire of the car is 400 N.