If 0.0900 g of a metal, M, reacts with excess hydrochloric acid to form 5.00*10(exp.)-3 moles of hydrogen gas and a solution of MCl(subscript)3. Calculate the molar mass of metal, M and identify it. The unbalanced equation is: M(s)+ HCl(aq) =>MCl(sub.)3 + H(sub)2.

Now that the SUBJECT has been stated, one of our chem teachers may notice it and respond

Balance the equation.

2M + 6HCl ==> 2MCl3 + 3H2

Convert moles H2 to moles M using the coefficients in the balanced equation.
0.0053 moles H2 x (2 moles M/3 moles H2) = 0.0053*(2/3) = 0.003333

moles = grams/molar mass and rearrange to
molar mass = grams/moles. You have grams in the problerm (0.0900 g) and moles from the calculation; solve for molar mass, then look on the periodic table to find a metal with that atomic mass.

To calculate the molar mass of the metal, M, we need to use the balanced chemical equation and the stoichiometry of the reaction.

Let's start by balancing the equation:
M(s) + 3HCl(aq) -> MCl3(aq) + H2(g)

According to the balanced equation, 1 mole of M reacts with 3 moles of HCl to produce 1 mole of MCl3 and 1 mole of H2.

We are given that 0.0900 g of M reacts to produce 5.00 * 10^(-3) moles of H2. We'll use the stoichiometry to find the number of moles of M.

First, we need to convert grams of M to moles using its molar mass, which we want to determine.
The formula to calculate the number of moles is: moles = mass / molar mass

Let's substitute the known values into the equation:
moles of M = 0.0900 g / molar mass of M

Now, let's find the molar mass of M by rearranging the equation:
molar mass of M = 0.0900 g / moles of M

To solve for the molar mass, we need to calculate the moles of M.
According to the stoichiometry, 1 mole of M reacts to produce 1 mole of H2.

Therefore, 5.00 * 10^(-3) moles of H2 is equivalent to 5.00 * 10^(-3) moles of M.

Now, let's substitute this value into the molar mass equation:
molar mass of M = 0.0900 g / (5.00 * 10^(-3) moles)

Calculating this expression will give the molar mass of M.

Once we have the molar mass, we can use the periodic table to determine the identity of the metal, M, by comparing its molar mass to the molar masses of known elements.