solve the inequality: -2<4z+10≤12
-2<4z+10≤12
subtract 10
-12 < 4z < 2
divide by 4
-3 < z < 1/2
-12<4z<=2
-3<z<=.5
Possibly... I'm not totally sure but it is a guess.
okay thanks!!
forgot the ≤
should have been
-2<4z+10≤12
subtract 10
-12 < 4z ≤ 2
divide by 4
-3 < z ≤ 1/2
chica is also correct
To solve the inequality -2 < 4z + 10 ≤ 12, we'll first isolate z.
-2 < 4z + 10 ≤ 12
Starting with the first inequality, -2 < 4z + 10, we'll subtract 10 from both sides to move the constant term to the opposite side:
-2 - 10 < 4z + 10 - 10
-12 < 4z
Next, we divide both sides by 4 to solve for z:
-12/4 < 4z/4
-3 < z
Now, let's solve the second inequality, 4z + 10 ≤ 12. We'll subtract 10 from both sides:
4z + 10 - 10 ≤ 12 - 10
4z ≤ 2
Then, divide by 4 on both sides to solve for z:
4z/4 ≤ 2/4
z ≤ 0.5
Therefore, combining both solutions, we have -3 < z ≤ 0.5.