College Chem
posted by Jennifer .
A diver exhales a bubble with a volume of 25 mL at a pressure of 2.4 atm and a temperature of 15 degrees C. how many gas particles are in this bubble?

I would use PV = nRT and solve for n = number of moles gas. One mole contains 6.022E23 molecules.

We did that and somehow got the wrong answer. can you please give me a step by step?
Thank you... 
n= PV/RT
n={(2.4)x(25)}/{(.082)x(288)
> n x 6.022x10^23 = answer 
niki has posted but the 25 mL must be inserted as 0.025 L

Thank you,
we were doing,
n=VRT
P
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