# Chemistry

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What is the pH when 25 mL of .20 M CH3COOH has been titrated with 35 mL of .10 M NaOH?

• Chemistry -

The pH is determined by the hydrolysis of the salt, CH3COONa.

CH3COO^- + HOH ==> CH3COOH + OH^-

Kb = (Kw/Ka) = (CH3COOH)(H3O^+)/(CH3COO^-)
Set up an ICE chart and substitute into the Kb equation. Solve for H3O^+ and convert to pH.

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