posted by Louis .
What is the pH when 25 mL of .20 M CH3COOH has been titrated with 35 mL of .10 M NaOH?
The pH is determined by the hydrolysis of the salt, CH3COONa.
CH3COO^- + HOH ==> CH3COOH + OH^-
Kb = (Kw/Ka) = (CH3COOH)(H3O^+)/(CH3COO^-)
Set up an ICE chart and substitute into the Kb equation. Solve for H3O^+ and convert to pH.