AP Calc BC

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Hi! Thank you for your help

How do you find the antiderivative of

"two over (x squared plus one)"
I think I have to do integration by partial fractions but I didn't figure it out...assistance is much appreciated
Thank you very much

  • AP Calc BC -

    A standard integral is
    =tan-1(x/a) + C

    If you have done substitution, you can evaluate the integral by substituting
    sec²(y)dy/dx=1/a, or
    =y + C
    =tan-1(x/a) + C

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