how do you write the chemical equation for liquid pentanol (C5H12O) and gaseous oxygen ?

Thanks

~Samantha~

To write the chemical equation for the reaction between liquid pentanol (C5H12O) and gaseous oxygen, we first need to determine the products of the reaction. Pentanol is an alcohol, which can undergo combustion in the presence of oxygen to produce carbon dioxide (CO2) and water (H2O).

The balanced chemical equation for the reaction would be as follows:

C5H12O + O2 -> CO2 + H2O

To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. For the number of carbon atoms, there are 5 on the left side (from C5H12O) and 1 on the right side (from CO2). Therefore, we need to add a coefficient of 5 in front of CO2:

C5H12O + O2 -> 5CO2 + H2O

Next, let's balance the hydrogen atoms. There are 12 on the left side (from C5H12O) and 2 on the right side (from H2O). To balance the hydrogens, we add a coefficient of 6 in front of H2O:

C5H12O + O2 -> 5CO2 + 6H2O

Finally, let's balance the oxygen atoms. There are 2 oxygen atoms on the left side (from O2) and 17 on the right side (from 5CO2 and 6H2O). To balance the oxygen atoms, we add a coefficient of 8 in front of O2:

C5H12O + 8O2 -> 5CO2 + 6H2O

So, the balanced chemical equation for the reaction between pentanol and oxygen is:

C5H12O + 8O2 -> 5CO2 + 6H2O