calculus
posted by lindy .
the side of squyare,s, is increasing at a rate of k unites per second. find the rate at which the area of the square is increasing

dx/dt=k units/s
A=x²
dA/dt = d(x²)/dt
=d(x²)/dx * dx/dt
=k* d(x³)/dx unit²/s
Can you take it from here?
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