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calculus

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the side of squyare,s, is increasing at a rate of k unites per second. find the rate at which the area of the square is increasing

  • calculus -

    dx/dt=k units/s

    A=x²
    dA/dt = d(x²)/dt
    =d(x²)/dx * dx/dt
    =k* d(x³)/dx unit²/s

    Can you take it from here?

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