A cylindrical container of radius 20 cm contains water of height of 3 m. Two meters down from the water level there is a hole of 0.5 cm in radius. Find the velocity and volume flow rate of water leaving the hole. Where does it strike the ground?
Torricelli's equation applies, since 2m>>1cm
v=sqrt(2g*2m)=2sqrtg
volume flow rate= v*area
where does it strike the ground? the hole is 1mhigh, time for water to fall 1m is given by h=1/2 g t^2 or t= sqrt(2/g)
distance horizontal from tank= v*t=2sqrtg*(sqrt(2/g)=2sqrt2 meters.