A box weighing 215 N is placed on an inclined plane that makes a 55 degree angle with the horizontal. Compute the component of the gravitional force acting down the inclined plane.
Given: W=215 N, <=55*
Find: F (parallel)
Solution: sin(<)=opp/hyp
opp =sin(<)(hyp)
F (parallel)=sin(55*)(215 N)
F (parallel)=176.1 N
Gravity is the parallel force that you're solving for because it is the force that makes the box slide down the incline. It's the y-component of weight when drawn on a vector diagram, but it's even understandable as a component of weight because weight=mg.
among us
Oh, just another case of gravity trying to be hip and going downhill. Well, the gravitational force can be divided into two components on the inclined plane: one parallel to the plane and the other perpendicular to it. Let's focus on the component parallel to the plane.
To find that bad boy, we need to use some trigonometry, because what's a little math between friends? The component of the gravitational force down the inclined plane can be calculated by multiplying the weight of the box (215 N) by the sine of the angle of inclination (55 degrees). So, grab your calculators, ready your trig functions, and let's do this!
Component = Weight x sine(angle)
Component = 215 N x sin(55 degrees)
Component = 215 N x 0.8192 (rounded to 4 decimal places because we're fancy like that)
Component ≈ 176 N.
So there you have it! The component of the gravitational force acting down the inclined plane is approximately 176 N. Now you know the gravity of the situation; it's all downhill from here!
To compute the component of the gravitational force acting down the inclined plane, we need to use trigonometry.
The gravitational force acting on the box can be represented by its weight, which is given as 215 N. This weight can be broken down into two components: one perpendicular to the inclined plane and one parallel to it.
First, let's find the component of the weight parallel to the inclined plane. We can use the formula:
F_parallel = Weight * sin(theta)
Where:
Weight = 215 N (the weight of the box)
theta = 55 degrees (the angle of the inclined plane with the horizontal)
Plugging in the values, we have:
F_parallel = 215 N * sin(55 degrees)
To get the final answer, we just need to evaluate this expression:
F_parallel = 215 N * sin(55 degrees) ≈ 175.34 N
Therefore, the component of the gravitational force acting down the inclined plane is approximately 175.34 N.