a sled mass 50 kg is pulled along snow-covered, flat group. the static friction coefficent is 0.30, and the sliding friction coefficient is .10. what force is need to get the sled moving? then, what force is needed to keep the sled moving at a constant velocity?
Is the word "group" supposed to be "ground"?
The force to start it moving is 0.30 M*g.
The force to keep it moving at constant speed is 0.10 M*g
easrtsr
It sucks
To find the force needed to get the sled moving, we need to consider static friction. The maximum static friction force can be calculated using the formula:
Maximum static friction force = Static friction coefficient * Normal force
In this case, the sled is on a flat surface, so the normal force is equal to the weight of the sled. The weight of the sled can be calculated using the formula:
Weight = Mass * Gravity
where the mass is 50 kg and the acceleration due to gravity is approximately 9.8 m/s^2. Therefore:
Weight = 50 kg * 9.8 m/s^2 = 490 N
Now, let's calculate the maximum static friction force:
Maximum static friction force = 0.30 * 490 N = 147 N
Therefore, a force of at least 147 N is required to get the sled moving.
To find the force needed to keep the sled moving at a constant velocity, we need to consider sliding friction. The sliding friction force can be calculated using the formula:
Sliding friction force = Sliding friction coefficient * Normal force
Again, the normal force is equal to the weight of the sled. Therefore, the sliding friction force can be calculated as:
Sliding friction force = 0.10 * 490 N = 49 N
So, a force of 49 N is needed to keep the sled moving at a constant velocity.