The ka expression for HTe- is?
Is that HTe^- as in H2Te that has lost a H^+?.
HT^- ==> H^+ + Te^-2
k2 = (H^+)(Te^-2)/(HTe^-)
To find the Ka expression for HTe-, we need to understand its chemical equation and the equilibrium constant expression.
The chemical equation for the dissociation of HTe- in water can be written as:
HTe- + H2O ⇌ Te2- + H3O+
The equilibrium constant expression, Ka, can be written as:
Ka = ([Te2-] * [H3O+]) / [HTe-]
In this equation, [Te2-], [H3O+], and [HTe-] represent the concentrations of Te2-, H3O+, and HTe- ions, respectively.
To find the Ka expression, you need to measure the concentrations of Te2-, H3O+, and HTe- in a solution and substitute them into the equation. The values for the concentrations can be determined experimentally or from a given set of conditions.
Note: The values in the Ka expression are in terms of concentrations, so it is essential to ensure that the units are consistent (usually expressed in mol/L).
Remember that the dissociation of HTe- is specific to a given reaction and will have its own unique Ka value based on the reaction conditions.