d=2.1 a=? vi=0 and t=.60 and i have to use the formula d=vit+1/2at^2, how do i do this? can you please show work so i can understand.
actually
x = Xi + Vi t + (1/2) a t^2
where
x = position
Xi = initial position
Vi = initial speed
a = acceleration
t = time
here
2.1 = 0 + 0 (.6) +(1/2) a (.6)^2
2.1 = (1/2)(.36) a
a = 4.2/.36
2.1=0(.6)+.5(a)(.6^2)
you can get drop the vit since vi=0. that will leave you with
2.1=.5a.6^2
multiply (.5)6^2 then you can divide 2.1 with the answer you got.
To solve for the final acceleration (a), you can use the formula d = vit + 1/2at^2. Given that d = 2.1, vi = 0, t = 0.60, and you need to find a, you can rearrange the formula to solve for a.
First, let's substitute the given values into the formula:
2.1 = (0)(0.60) + (1/2)a(0.60)^2
The term (0)(0.60) becomes zero, so we're left with:
2.1 = (1/2)a(0.60)^2
Next, simplify the equation:
2.1 = (1/2)a(0.36)
Multiply 0.36 by (1/2) to simplify further:
2.1 = 0.18a
Now, divide both sides of the equation by 0.18 to solve for a:
a = 2.1 / 0.18
Calculating the division:
a ≈ 11.67
Therefore, the final acceleration (a) is approximately 11.67.