Calculate the energy of a photon of electromagnetic radiation at each of the following frequencies.
(A) 103.1 MHz (typical frequency for FM radio broadcasting)
(B) 1015 kHz (typical frequency for AM radio broadcasting) (assume four significant figures)
835.6 MHz (common frequency used for cell phone communication)
For part A i got these (in J)but they are wrong: 1.93×10^−32, 6.83×10^−25, 6.83×10^−24, 6.83×10^−23
For part B i got this, but it is wrong too: 6.96×10^−26
E=hf=plancksconstant*103.1E6
=6.626E-34 J s*103.1E6 which does not agree with your answer. Redo them.
How do you possibly list four answers for a)?
6.725x10^-28
The energy of a photon can be calculated using the formula:
E = hf
where E is the energy of the photon, h is the Planck's constant (6.626 x 10^-34 J·s), and f is the frequency of the electromagnetic radiation.
Let's calculate the energy of the photons at the given frequencies:
(A) 103.1 MHz (1 MHz = 10^6 Hz)
f = 103.1 MHz = 103.1 x 10^6 Hz
E = (6.626 x 10^-34 J·s) x (103.1 x 10^6 Hz)
E ≈ 6.84 x 10^-26 J (rounded to three significant figures)
(B) 1015 kHz (1 kHz = 10^3 Hz)
f = 1015 kHz = 1015 x 10^3 Hz
E = (6.626 x 10^-34 J·s) x (1015 x 10^3 Hz)
E ≈ 6.72 x 10^-26 J (rounded to three significant figures)
(C) 835.6 MHz (1 MHz = 10^6 Hz)
f = 835.6 MHz = 835.6 x 10^6 Hz
E = (6.626 x 10^-34 J·s) x (835.6 x 10^6 Hz)
E ≈ 5.52 x 10^-26 J (rounded to three significant figures)
So, the correct answers are:
(A) 6.84 x 10^-26 J
(B) 6.72 x 10^-26 J
(C) 5.52 x 10^-26 J
To calculate the energy of a photon of electromagnetic radiation, you can use the equation:
E = hf
where E is the energy of the photon, h is Planck's constant (6.62607015 × 10^-34 J·s), and f is the frequency of the radiation.
Let's calculate the energy for each given frequency:
(A) 103.1 MHz (megahertz):
First, convert the frequency from MHz to Hz:
103.1 MHz = 103.1 × 10^6 Hz
Next, substitute the frequency value into the equation:
E = (6.62607015 × 10^-34 J·s) × (103.1 × 10^6 Hz)
Calculate the value:
E ≈ 6.83 × 10^-27 J
(B) 1015 kHz (kilohertz):
First, convert the frequency from kHz to Hz:
1015 kHz = 1015 × 10^3 Hz
Next, substitute the frequency value into the equation:
E = (6.62607015 × 10^-34 J·s) × (1015 × 10^3 Hz)
Calculate the value:
E ≈ 6.76 × 10^-28 J
(C) 835.6 MHz:
First, convert the frequency from MHz to Hz:
835.6 MHz = 835.6 × 10^6 Hz
Next, substitute the frequency value into the equation:
E = (6.62607015 × 10^-34 J·s) × (835.6 × 10^6 Hz)
Calculate the value:
E ≈ 5.53 × 10^-25 J
Therefore, the correct energies for the given frequencies are:
(A) 103.1 MHz: 6.83 × 10^-27 J
(B) 1015 kHz: 6.76 × 10^-28 J
(C) 835.6 MHz: 5.53 × 10^-25 J