In Hydration of 2-Ethyl-1-Butene which is the major product and which is the minor product? possible products are 3-methyl-3-pentsnol with a bp of 123C and 2-ethyl-1-butanol with a bp of 146C.

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To determine the major and minor products in the hydration of 2-Ethyl-1-Butene, we need to consider the mechanism of the reaction.

The hydration of an alkene typically proceeds through an acid-catalyzed mechanism called the Markovnikov's rule. According to this rule, the major product is obtained by adding the hydroxy group (OH) to the carbon atom that has the greater number of hydrogen atoms attached to it (the more substituted carbon). The minor product is formed by adding the hydroxy group to the other carbon atom (the less substituted carbon).

In the case of 2-Ethyl-1-Butene, let's designate the carbon atoms as follows:
CH3 - CH(CH3) - CH2 - CH=CH2
Carbon1 Carbon2 Carbon3

To determine the major product, we look at the more substituted carbon, which is Carbon2. Hence, the major product will be formed by adding the hydroxy group to Carbon2 (the more substituted carbon).
Therefore, the major product is 2-Ethyl-1-Butanol.

To determine the minor product, we look at the less substituted carbon, which is Carbon3. Hence, the minor product will be formed by adding the hydroxy group to Carbon3 (the less substituted carbon).
Therefore, the minor product is 3-Methyl-3-Pentanol.

Based on their boiling points, 2-Ethyl-1-Butanol has a higher boiling point (146°C) compared to 3-Methyl-3-Pentanol (123°C). Thus, 2-Ethyl-1-Butanol will be the major product.

In summary, the major product of the hydration of 2-Ethyl-1-Butene is 2-Ethyl-1-Butanol, and the minor product is 3-Methyl-3-Pentanol.