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Concentration calculations
how many grams of KCL are required to make 5.0ml of a 35% w/v solution?
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unsaturated Solution
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a solution is prepared with 3.26g kcl and water to make 25.0ml,of kcl,what is the %(m/V) of the kcl solution.
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13.04%
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If 32.3 grams of KCl are dissolved in 192 grams of water, what is the concentration of the solution in percent by mass?
5.94% KCl
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To find the concentration of a solution in percent by mass, you need to divide the mass of the
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a solution of kcl contains 10. grams of kcl in 100. ml of water at 30c. how many additional grams of kcl are needed to saturate
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I don't have all of the solubility tables memorized for all of the salts. There must be thousands.
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If 30 grams of KCl is dissolved in 100 grams of water at 40 degrees celsius, how many additional grams of KCl would be needed to
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30 grams
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9.7g ofamixture of KOH and KCL was to
disolve to make 1litre solution.20cm of this solution required 25.0cm of 0.12Molarity HCL
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NOTE: You mean 20 mL or 20 cc or 20 cm^3 and not 20 cm. KOH + HCl ==> KCl + H2O millimols HCl = mL x
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How many grams of KCl are required to make .75 L of 0.29 M solution? Round to one decimal place.
i got .2907 is this correct im
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massingrams=molmassKCl*.75*.29
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What mass of KCl \rm KCl is needed to precipitate the silver ions from 13.0mL mL of 0.200 M M AgNO 3 \rm AgNO_3 solution
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AgNO3(aq) + KCl(aq) ==> AgCl(s) + KNO3(aq) mols AgNO3 = M x L = ? mols KCl = the same (Look at the
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Can you please check my answer?
Balance the following equation: Cl2 + KI --> I2 + KCl How many grams of Cl2 are used to form 6.8
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Cl2 + 2KI --> I2 + 2KCl 6.8gKCl*1molKCl/74.55gKCl*1molCL2/2MolKCl* 70gCL2/1molCl2
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A student stated that the solubility of KCl at 20 degrees Celsius was 36 grams of KCl per 100 grams of solution. What is wrong
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solubility is in moles or grams solute/mass solvent, not per mass solution
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A student stated that the solubility of KCL, at 20 degrees Celsius was 36 grams of KCL per 100 grams of solution. What is wrong
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see other post
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