In hydration of of 2-Ethyl-1-Butene
What important bands (include wavenumbers) would begin to disappear in an IR
spectrum and what important bands would begin to appear in the IR spectrum as
the reaction progressed?
The double bond band begins to disappear and the OH stretching and OH bending begin to appear. You can find the wavenumber of those bands in a table.
Thank you so much DrBob!!!!
To determine the changes in the IR spectrum during the hydration of 2-Ethyl-1-Butene, we need to understand the functional groups present in the reactant and the product molecules.
In 2-Ethyl-1-Butene, the important functional group is the carbon-carbon double bond, also known as an alkene. During hydration, this alkene will react with water, resulting in the formation of an alcohol functional group (hydroxyl group).
As the reaction progresses, the following changes in the IR spectrum are expected:
1. Disappearance of the alkene/stretching absorption band: In the IR spectrum of 2-Ethyl-1-Butene, a characteristic absorption band for alkene stretching vibrations is observed around 1600-1680 cm^-1. As the reaction proceeds, this band will gradually disappear since the carbon-carbon double bond is being converted into an alcohol group.
2. Appearance of the O-H/stretching absorption band: In the IR spectrum of the product, an important band that appears is the O-H stretching vibration. This absorption typically occurs in the range of 3200-3600 cm^-1, indicating the presence of the newly formed alcohol group.
It is worth noting that in addition to these changes, there may be other subtle variations in the IR spectrum due to the presence of other functional groups in the reactant and product molecules. However, the disappearance of the alkene stretching band and the appearance of the O-H stretching band are the most significant changes expected in the IR spectrum during the hydration of 2-Ethyl-1-Butene.