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An 879-kg (1943 lb) dragster, starting from rest, attains a speed of 25.6 m/s (57.3 mph) in 0.59 s.
(a) Find the average acceleration of the dragster during this time interval.

(b) What is the magnitude of the average net force on the dragster during this time?

  • physics -

    I am not going to do all these for you. They are all basically the same.

    a = (V2-V1)/t = (25.6-0)/.59 = 43.4 m/s^2

    F = m a = 879 * 43.4 = 38,140 Newtons

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