An ordinary glass is filled to the brim with 350.0 mL of water at 100°C. If the temperature decreased to 19°C, how much water could be added to the glass?
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To figure out how much water could be added to the glass, we need to calculate the change in volume due to the change in temperature.
The change in volume of water can be calculated using the formula:
ΔV = (V × α × ΔT)
Where:
ΔV is the change in volume
V is the initial volume of water
α is the coefficient of thermal expansion of water (0.00021 1/°C)
ΔT is the change in temperature
Given:
V = 350.0 mL (or 350.0 cm³)
ΔT = 100°C - 19°C = 81°C
Let's plug in the values into the formula:
ΔV = (350.0 cm³ × 0.00021 1/°C × 81°C)
ΔV ≈ 5.469 cm³
So the change in volume of water is approximately 5.469 cm³.
To find out how much water could be added to the glass, we can convert this change in volume to milliliters (mL).
1 cm³ = 1 mL
Therefore, the amount of water that could be added to the glass is approximately 5.469 mL.