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A rectangle has length & width in the ratio of 3:2.If the length is increased by 8 & width is increased by 50%.The ratio of new perimeter to original perimeter is 8:5.Find the area of new rectangle

  • maths -

    let the length be 3x and
    let the width be 2x

    new length = 3x + 8
    new width = 1.5(2x) = 3x

    original perimeter = 2(3x) + 2(2x) = 10x
    new perimeter = 2(3x+8)+ 2(3x)
    = 12x + 16

    (12x+16)/(10x) = 8/5
    80x = 60x + 80
    20x = 80
    x = 40
    so new length = 3(40)+8 = 128
    new width = 3(40) = 120
    new area = 128x120 = 15360

    use the suitable units, you gave none.

  • error - maths -

    "20x = 80
    x = 40 "

    How silly of me ! , that should have been

    x = 4
    so new rectangle is 20 by 12 for an area of 240

  • maths -

    5yd 6yd u

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